Changeset 502 in svn
- Timestamp:
- Jul 21, 2009, 10:47:30 AM (15 years ago)
- Location:
- trunk/paper
- Files:
-
- 4 edited
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trunk/paper/CommPhysComp/notes.tex
r501 r502 506 506 %\includegraphics[width=0.6\columnwidth]{Tau} 507 507 \includegraphics[width=0.80\columnwidth]{fig5} 508 \caption{Illustration of the identification of $\tau$-jets ($1-$prong). The jet cone is narrow and contains only one track. The small cone s hown as the red one is used for the \textit{electromagnetic collimation}, while the green cone is the cone radius used to reconstruct the jet originating from the $\tau$-decay.}508 \caption{Illustration of the identification of $\tau$-jets ($1-$prong). The jet cone is narrow and contains only one track. The small cone serves to apply the \textit{electromagnetic collimation}, while the broader cone is used to reconstruct the jet originating from the $\tau$-decay.} 509 509 \label{h_WW_ss_cut1} 510 510 \end{center} -
trunk/paper/notes.tex
r499 r502 459 459 \begin{figure}[!h] 460 460 \begin{center} 461 \includegraphics[width=0. 6\columnwidth]{Tau}462 \caption{Illustration of the identification of $\tau$-jets ($1-$prong). The jet cone is narrow and contains only one track. The small cone s hown as the red one is used for the \textit{electromagnetic collimation}, while the green cone is the cone radius used to reconstruct the jet originating from the $\tau$-decay.}461 \includegraphics[width=0.96\columnwidth]{Tau} 462 \caption{Illustration of the identification of $\tau$-jets ($1-$prong). The jet cone is narrow and contains only one track. The small cone serves to apply the \textit{electromagnetic collimation}, while the broader cone is used to reconstruct the jet originating from the $\tau$-decay.} 463 463 \label{h_WW_ss_cut1} 464 464 \end{center} … … 624 624 Similarly, the jet resolution is evaluated for an \textsc{atlas}-like detector. The $pp \rightarrow gg$ events are here arranged in $8$ adjacent bins in $p_T$. A $k_T$ reconstruction algorithm with $R=0.6$ is chosen and the maximal matching distance between the \textsc{mc}-jets and the reconstructed jets is set to $\Delta R=0.2$. The relative energy resolution is evaluated in each bin by: 625 625 \begin{equation} 626 \frac{\sigma(E)}{E} = \sqrt{ ~~ \Bigg \langle ~\Bigg( \frac{E^\textrm{rec} - E^\textrm{MC}}{E^\textrm{rec}} \Bigg)^2 ~ \Bigg \rangle ~ - ~\Bigg \langle \frac{E^\textrm{rec} - E^\textrm{MC}}{ E^\textrm{rec} } \Bigg \rangle^2}.626 \frac{\sigma(E)}{E} = \sqrt{ \Bigg \langle \Bigg( \frac{E^\textrm{rec} - E^\textrm{MC}}{E^\textrm{rec}} \Bigg)^2 \Bigg \rangle - \Bigg \langle \frac{E^\textrm{rec} - E^\textrm{MC}}{ E^\textrm{rec} } \Bigg \rangle^2}. 627 627 \end{equation} 628 628
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